Table of contents
- What is the cable cross-section?
- Why is the cable cross-section so important?
- How is the cable cross-section / conductor cross-section calculated?
- How is the cable cross-section calculated in relation to the voltage?
- How is the cable cross-section calculated in relation to the amperage?
- How is the cable cross-section calculated in relation to the power?
- Excursus: Cable cross-section for walboxes and PV systems
- Cable cross-section for power cables, underground cables and domestic installations
- Which fuse for which cable cross-section?
- Further questions on the subject of cable cross-section
Reliable and adequately dimensioned cabling is the be-all and end-all for power supply in the private and industrial sectors. After all, if you cut corners with the wiring and choose a cable cross-section that is too small for the power of the connected loads, premature wear of the wires, a short circuit or a cable fire can result in high consequential costs.
Under certain circumstances, it can also cause problems with the insurance company. Our guide contains useful tips and clarifies the most important questions about cable cross-sections.
What is the cable cross-section?
The cable cross-section or wire cross-section is the cross-sectional area of the metal conductors. As a rule of thumb, the larger the cross-sectional area of the conductors in a cable, the greater the current carrying capacity. The cable cross-section is given in mm² and thus provides information about the surface area of the round cable section. Important: The cable cross-section is not the same as the diameter of the cable, as this is a length measurement.
Cross-sectional area of the conductor: A distinction is made between the geometrically defined nominal cross-section and the conductive cross-section, which is derived from the electrical resistance. The nominal cross-section is specified in square millimetres. However, it is not defined as a geometric cross-section, but as the electrically effective cross-section of the conductor at 20°C. Compliance with the nominal cross-section must be verified during the final inspection of the product and is also one of the focal points of the self-checks in the ongoing production inspections.
A certain maximum resistance is assigned to the nominal cross-section, within which the conductor structure is also specified. As a rule, the cross-section is specified in mm². However, for certain types of wires and cables, which are always made up of single-wire conductors (telecommunications cables), the conductor diameter is used for labelling or description purposes.
Here you will find all the diameters of the individual cable cross-sections clearly presented in a table:
| Cable cross-sections standardised in accordance with IEC 60228 and VDE 0295 | Diameter of the conductor |
|---|---|
| 0.25 mm² | ~0.56mm |
| 0.34 mm² | ~0.66mm |
| 0.5 mm² | ~0.80mm |
| 0.75 mm² | ~0.98 mm |
| 1 mm² | ~1.13 mm |
| 1.5 mm² | ~1.38 mm |
| 2.5 mm² | ~1.78 mm |
| 4 mm² | ~2.26 mm |
| 6 mm² | ~2.76 mm |
| 10 mm² | ~3.57 mm |
| 16 mm² | ~4.51 mm |
| 25 mm² | ~5.64 mm |
| 35 mm² | ~6.68 mm |
| 50 mm² | ~7.98 mm |
| 70 mm² | ~9.44 mm |
| 95 mm² | ~11 mm |
| 120 mm² | ~12.40 mm |
| 150 mm² | ~13.82 mm |
| 185 mm² | ~15.35 mm |
| 240 mm² | ~17.48 mm |
| 300 mm² | ~19.54 mm |
| 400 mm² | ~22.57 mm |
| 500 mm² | ~25.23 mm |
| 630 mm² | ~28.32 mm |
| 800 mm² | ~31.91 mm |
| 1000 mm² | ~35.68 mm |
What standards are there for cable cross-sections?
The internationally recognised standard IEC 6022 refers to the conductor cross-section of insulated cables and is equivalent to the cable cross-section DIN standard DIN EN 60228 and the conductor cross-section standard VDE 0295.
What does the required cable cross-section depend on?
As a rule of thumb, the more power required, the larger the cable cross-section.
Why is the cable cross-section so important?
One of the most frequently asked questions in electrical installation is: Which values have an influence on the cable cross-section to be selected? In addition to the voltage, the amount of current to be conducted and the power, the length of the cable must also be taken into account when selecting a suitable cable cross-section.
You can find more information on the topic of current/voltage in our guide article "How is electrical voltage measured and calculated?".
How do I recognise the cable cross-section?
A wire gauge is suitable for measuring the cable cross-section of a wire. You can also use a caliper gauge to determine the cable cross-section. For multi-core cables with fine strands, it is advisable to measure the cable cross-section with insulation so that accidental compression does not falsify the measurement.
Please also bear in mind that the diameter of the cables including insulation varies from manufacturer to manufacturer. If in doubt, it is therefore advisable to determine the cable cross-section of the single core cables. With some cables, the cable cross-section can also be recognised by the imprint on the sheath.
What happens if the cable cross-section is too small or too large?
A large cable cross-section primarily results in higher costs and, as it is less flexible, you can expect the cable to be more complex to lay.
The longer and thinner a wire is, the greater the risk of heat build-up, which in turn increases the resistance of the conductor. In the worst case, this can melt the insulation and cause a fire. For this reason, cable cross-sections in all electrical systems are always selected larger the longer the cable is. Voltage drops are compensated for by using larger cross-sections, thus ensuring that a voltage of 230V is present in the cable network, for example.
Is the cable cross-section the same as the cable diameter?
The cable cross-section is an area measurement (in mm²) and the cable diameter is a length measurement (in mm). These can be calculated using simple formulae. In electrical engineering in particular, it is sometimes important to calculate the cable diameter in cable cross-section.
Calculate the cable cross-section from the cable diameter using the formula:
A=r² * π = d² * π/4
or
Calculate the cable diameter from the cable cross-section using the formula
d=2 * √A/ π = 2 * r
or
Note: the thickness of the insulation and the separating air for stranded wires musthave atotal diameter that is around 14 % larger than that of a solid wire due to the individual wires lying next to each other.
How is the cable cross-section / conductor cross-section calculated?
A frequently asked question is: What values are needed to calculate the cable cross-section? In fact, you only need a few parameters. To calculate the cable cross-section (A), e.g. for direct current, you need the following values: current in amperes (I), length of the cable (L), voltage drop (Ua), as well as the specific conductance Kappa copper (y) and the voltage (U). The complete formula for calculating the cable cross-section is as follows:
A = (2 x I x L) / (y x Ua x U)
No time to do the maths? Instead of calculating the optimum cable cross-section using this rule of thumb, you can also consult our cable cross-section table.
| Cable cross-sections standardised in accordance with VDE 0295 for 12 V DC applications | Maximum current in amperes |
|---|---|
| 1 mm² | 11A |
| 1.5 mm² | 15A |
| 2.5 mm² | 20A |
| 4 mm² | 25A |
| 6 mm² | 33A |
| 10 mm² | 45A |
| 16 mm² | 61A |
| 25 mm² | 83A |
| 35 mm² | 103A |
| 50 mm² | 132A |
| 70 mm² | 165A |
| 95 mm² | 197A |
| 120 mm² | 235 A |
If you use three-phase current, you can also calculate the cable cross-section. In addition to the voltage, you also need information on the efficiency and power. As with AC applications, the design of the cable cross-section must be increased with increasing voltage and power.
Calculate cable cross-section, power and amperage
Calculate the cable cross-section (three-phase current / alternating current) quickly and easily.
Calculate the cable cross-section (three-phase current / alternating current) quickly and easily.
Current-carrying capacity of cables and lines This information on current-carrying capacity up to a cross-section of 35 mm² refers to multi-core cables laid permanently in a building, e.g. in an installation pipe, with max. 3 loaded outer conductors at an ambient temperature of 25°C. The specifications for cross-sections of 50 mm² and ascending refer to multi-core cables laid in the ground with max. 3 loaded outer conductors at an ambient temperature of 20°C.
- Formula for calculation - three-phase current A = 1,732 * L * ((kW * 1000) / (U * 1,732)) * cos(y * Ua)
- Formula for calculation - alternating current A = 2 * L * I * cos φy * Ua
- A = Conductor cross-section of the single wire in mm²
- L = Single conductor length in metres
- I = Conductor current (current of the single core) in A/span>
- cos φ = Efficiency - inductive / capacitive load (in practice 0.9 to 1)
- y = Conductivity of copper (56) or aluminium (37)
- Ua = Voltage drop in volts
- 1,732 = Interlinking factor (√ 3)
- U = Mains voltage in volts
Calculate the power (three-phase current / alternating current) quickly and easily.
- Formula for calculation - three-phase current P = U * I * 1,73
- Formula for calculation - alternating current P = U * I
- P = Power in watts
- U = Voltage in volts
- I = Current in amperes
Calculate the current strength (three-phase current / alternating current) quickly and easily.
- Formula for calculation - three-phase current I = P / (U*1,73)
- Formula for calculation - alternating current I = P / U
- P = Power in watts
- U = Voltage in volts
- I = Current in amperes
Cable calculation based on voltage drop
- When selecting the cable, it is important to consider not only the possible current carrying capacity depending on the type of installation, but also the voltage drop that occurs during normal operation.
- Permissible voltage drops are, for example, 0.5 % from the house connection box (HAK) to the meter point and max. 3 % from the meter point to the last consumer.
- Voltage drop means that the desired 230/400 V, for example, no longer arrive at the end of the line during normal operation, but less according to the calculation.
- Voltage drop also means power loss via the line. This is power that is missing at the end of the line, but is recorded by the meter and therefore also represents a cost factor.
- The voltage drop depends on the cable length, the cable cross-section, the mains voltage, e.g. 230/400 V or, in the case of low voltages, e.g. 12/24 V DC, and the current that must flow through the cable.
- We provide our calculator by entering the current in amperes (A) or alternatively by entering the power in kilowatts (KW) if the current specification is unknown. The last factor that plays a role is the cos φ. This is the ratio between apparent power, active power and reactive power. If no information is available, you should assume a factor of 0.9 - 1.
- After the calculation, an indication appears in qmm, this is purely arithmetical, when selecting, the next higher value must be selected accordingly.
How is the cable cross-section calculated in relation to the voltage?
This is how you calculate the cross-section:
To calculate the cable cross-section in relation to the voltage, use the formula for alternating current (230V):
A = 2 * L * I * cos φ / y * Ua
Again,A stands for the cable cross-section in mm², L for the simple cable length in metres, I indicates the current of the single core cables in amperes and cos φ indicates the efficiency, which is usually between 0.9 and 1. The y stands for the conductivity, which is 58 in the case of copper and 37 in the case of aluminium. The parameter Ua characterises the voltage drop in volts.
Using this method, you can easily calculate how large the cable cross-section should be, e.g. for a 230 volt domestic power line, or the cable cross-section for low voltage.
| Maximum power with a cable length of up to 10 metres | Recommended cable cross-section at 230 V in mm² | Recommended cable cross-section at 400 V in mm² |
|---|---|---|
| 1,000 watts | 2.5 mm² | 1.5 mm² |
| 1,200 watts | 2.5 mm² | 1.5 mm² |
| 1,500 watts | 2.5 mm² | 1.5 mm² |
| 1,800 watts | 2.5 mm² | 1.5 mm² |
| 2,100 watts | 2.5 mm² | 1.5 mm² |
| 3,500 watts | 2.5 mm² | 1.5 mm² |
Product recommendations
What cable cross-section for 12V?
To calculate the cable cross-section (A) for 12V consumers, you can use the following formula:
A = (I * 0.0175 * L * 2) / (fk * U).
I = max. current in amperes
L = cable length
fk = loss factor in per cent divided by 100 (e.g. fk 2% = 0.02)
U = voltage
0.0175 gives the specific resistance of copper in ohms x mm² / m.
If a standardised cable cross-section is to be used for 12V consumers, refer to the following table. Here you can also see how large the 12V cable cross-section should be for the respective power in amperes.
Example: A=(9.1A x 0.0175 x 1.5m x 2) / (0.02 x 12V)
| Cable cross-sections standardised according to IEC 60228 and VDE 0295 for 12V applications | Maximum current in amperes |
|---|---|
| 1 mm² | 11A |
| 1.5 mm² | 15A |
| 2.5 mm² | 20A |
| 4 mm² | 25A |
| 6 mm² | 33A |
| 10 mm² | 45A |
| 16 mm² | 61A |
| 25 mm² | 83A |
| 35 mm² | 103A |
| 50 mm² | 132A |
| 70 mm² | 165A |
| 95 mm² | 197A |
| 120 mm² | 235 A |
The cable cross-section of your vehicle's 12V electrical system must also be designed for the high output of a starter battery.
For 100 A at 12V, it is recommended to use wires with a cable cross-section of at least 35 mm².
Which cable cross-section for 24V?
A sufficient cable cross-section is not only important for 230V consumers in the home. It is also recommended in motorhomes or when using LED lighting with 24V. The following table lists the recommended cable cross-sections for a cable length of 3 metres and an output of up to 1000 watts.
| Cable cross-sections for 24V applications with 3 metre cable length | Power in watts |
|---|---|
| 1.5 mm² | 100 Watt |
| 3 mm² | 200 Watt |
| 4.5 mm² | 300 watts |
| 6 mm² | 400 watts |
| 7.5 mm² | 500 watts |
| 9 mm² | 600 watts |
| 10.5 mm² | 700 watts |
| 12 mm² | 800 watts |
| 13.5 mm² | 900 watts |
| 15 mm² | 1,000 watts |
What cable cross-section for 230V?
To calculate the cable cross-section for 230V, use the following formula:
A = 2 * L * I * cos φ / y * Ua.
A = cable cross-section in mm²
L = cable length in metres
I = conductor current in amperes
cos φ = efficiency (between 0.9 and 1)
y = Conductivity (copper 58, aluminium 37)
Ua = voltage drop in volts.
| Cable cross-sections for 230V applications with a cable length of 10 metres | Power in kW | Current in amperes |
|---|---|---|
| 1.5 mm² | 3.5 kW | ~15A |
| 2.5 mm² | 5.5 kW | ~23A |
| 4.0 mm² | 6.5 kW | ~28A |
| 6.0 mm² | 7.5 kW | ~32A |
| 10.0 mm² | 12 kW | ~52A |
| 16 mm² | 16 kW | ~65A |
| 25 mm² | 22 kW | ~95A |
What cross-section for 400V?
To calculate the cable cross-section on a 3-phase 400V wire, you need the following formula:
A = 1.732 * L * I * cos φ / y * ua * U
or
A = √3* L * I * cos φ / y * ua * U
A = Cable cross-section single core cables in mm²
L = cable length in metres
I = conductor current in amperes
cos φ = efficiency (between 0.9 and 1)
y = Conductivity (copper 58, aluminium 37)
ua = voltage drop in %
U = Mains voltage in volts
1.732 (or √ 3) = Interlinking factor (ratio of the electrical voltage between two neighbouring outer conductors)
| Cable cross-sections for 400V applications with a cable length of 10 metres | Power in kW | Current in amperes |
|---|---|---|
| 1.5 mm² | 3.5 kW | ~5A |
| 1.5 mm² | 4.5 kW | ~6.5A |
| 1.5 mm² | 5.5 kW | ~8A |
| 1.5 mm² | 6.5 kW | ~9.4A |
| 1.5 mm² | 7.5 kW | ~11A |
| 2.5 mm² | 12 kW | ~17.3A |
| 4 mm² | 16 kW | ~23A |
| 6 mm² | 22 kW | ~32A |
How is the cable cross-section calculated in relation to the amperage?
The current carrying capacity, or maximum current that is permissible for a cable cross-section, can be calculated for direct current, alternating current and three-phase current applications. You will need the following formulae for the calculation:
Formula cable cross-section for three-phase current: A= √3 * L * I * cos φ / y * ua * U
If you insert the values accordingly, you get the value for the cable cross-section (A) in mm², which is recommended for the respective current in amperes or power in watts.
Formula cable cross-section for direct current: A= 2 * L * I / y * ua * U
| Cable cross-sections for 24V applications with 3 metre cable length | Power in watts | Current in amperes |
|---|---|---|
| 1.5 mm² | 100 Watt | 4.2A |
| 3 mm² | 200 Watt | 8.3A |
| 4.5 mm² | 300 Watt | 12.5A |
| 6 mm² | 400 Watt | 16.7A |
| 7.5 mm² | 500 Watt | 20.8A |
| 9 mm² | 600 Watt | 25A |
| 10.5 mm² | 700 Watt | 29.2A |
| 12 mm² | 800 Watt | 33.3A |
| 13.5 mm² | 900 Watt | 37.5A |
| 15 mm² | 1,000 watts | 41.7A |
The following table shows which cable cross-section you should select depending on the current in amperes, which specifies the load capacity of wires with rated voltages up to 1000V in accordance with VDE 0298-4.
| Cable cross-section in mm² | Single-core and heat-resistant wires laid freely in the air. Insulated with rubber or PVC | Multicore and heat-resistant wires laid on or on surfaces (excluding domestic or hand-held appliances). Insulated with rubber or PVC |
|---|---|---|
| 0.75 mm² | 15A | 12A |
| 1 mm² | 19A | 15A |
| 1.5 mm² | 24A | 18A |
| 2.5 mm² | 32A | 26A |
| 4 mm² | 42A | 34A |
| 6 mm² | 54A | 44A |
| 10 mm² | 73A | 61A |
| 16 mm² | 98A | 82A |
| 25 mm² | 129A | 108A |
| 35 mm² | 158A | 135A |
| 50 mm² | 198A | 168A |
| 70 mm² | 245A | 207A |
| 95 mm² | 292A | 250A |
| 120 mm² | 344A | 292A |
Which cable cross-section do you need to select for high voltage or three-phase current?
What cable cross-section do you need to select for heavy current or three-phase current? In principle, the recommended cable cross-section increases with increasing current in amperes.
How many amperes for which cross-section at 400V?
From 5 amps, wires with 1.5 mm² are recommended.
From 16 amps, wires with 1.5 mm² are recommended.
From 17.3 amps, wires with 2.5 mm² are recommended.
From 20 amps, wires with 2.5 mm² are recommended.
From 23 amps, wires with 4 mm² are recommended.
From 32 amps, a 6 mm² wire is recommended.
How many amps for which cross-section at 230V?
From 10 amps, wires with 2.5 mm² are recommended.
From 16 amps, wires with 2.5 mm² are recommended.
From 32 amps, wires with 4 mm² are recommended.
From 50 amps, wires with 10 mm² are recommended.
From 63 amps, a 16 mm² wire is recommended.
From 100 amps, a 35 mm² wire is recommended.
From 125 amps, wires with 50 mm² are recommended.
From 180 amps, wires with 95 mm² are recommended.
From 230 amps, we recommend using wires with 120 mm².
Excursus: Cable cross-section for wallboxes
Which cable cross-section for wallboxes?
The recommended cable cross-section for a wallbox depends on the maximum power in kW. For example, the supply cable for a wallbox should be 3-phase (400V) with 11 kW power and have a cable cross-section of at least 2.5 mm² ; 6 mm² is recommended. For a charging station 1-phase (230V) with 3.7 kW, the recommended cable cross-section is 6 mm².
Recommended cable cross-section of a charging station (wallbox) for an electric car at a glance:
| Voltage (V) | Current (A) | Network | max. power (kW) | Conductor cross-section (mm²) | |
|---|---|---|---|---|---|
| Recommended | at least | ||||
| 230 V | 10A | 1-phase | 2.3 | 6 | 2.5 |
| 230 V | 16A | 1-phase | 3.7 | 6 | 2.5 |
| 230 V | 32A | 1-phase | 7.4 | 10 | 4 |
| 400 V | 16A | 3-phase | 11 | 6 | 2.5 |
| 400 V | 32A | 3-phase | 22 | 10 | 4 |
The operation of a charging station for an electrically powered car not only requires the recommended cable cross-section of the supply line: When connecting a wallbox, e.g. with 22 kW power, you must comply with the correct cable cross-section and obtain authorisation from your network operator.
If the cable cross-section in a motorhome is too small, a charging booster can help. It counteracts a voltage drop if a consumer with a power of 10 A is operated on a cable with a cross-section of only 2.5 mm².
Cable cross-section for power cables, underground cables and house installations
A common question is: What cable cross-section should you choose for sockets? As a rule, a cable cross-section of 1.5 mm² is sufficient for individual sockets in a conventional house installation; if there are several sockets on a single-phase wire, the cross-section should be at least 2.5 mm².
What cable cross-section for house connection? The cross-section must be at least 16 mm².
What cable cross-section for underground cables?
The recommended cable cross-section for underground cables to supply house connections or building supply lines should be 16 or 25 mm². For individual consumers, e.g. in the garden, 1.5 mm² to 2.5 mm² is sufficient, depending on the application and power of the consumer.
What cross-section for power cables?
For NYM cables, the respective cable cross-section is standardised according to DIN VDE 0295 and IEC 60228.
How much power (watts) or current (amperes) can a NYM power cable withstand? In this case too, the sizes of the cross-section depend on the maximum power of the consumer and the cable length. NYM cables with a cross-section of 1.5, 2.5 or 4 mm² are mainly used in the home.
Our NYM table provides information on the common NYM cables, whose cable cross-section has already been derived from the respective diameter.
| Common NYM cables | Protective conductor | Number of cables x cross-section in mm² |
|---|---|---|
| NYM-J (earthing cable) | with protective conductor | 1x4mm² |
| NYM-J | with protective conductor | 3x1.5mm² |
| NYM-J | with protective earth | 3x2.5mm² |
| NYM-O | without protective earth | 4x10mm² |
| NYM-JZ | with protective conductor and tensile strength | 7x1.5mm² |
| NYM-OZ | without protective conductor and tensile strength | 7x1.5mm² |
Further questions on the subject of cable cross-sections
Finally, we answer other frequently asked questions on the subject of cable cross-sections.
Which cable cross-section for which cable length?
In principle, the cable cross-section to be selected is also determined by the power loss, which depends on the respective cable length, among other things. The longer the wires, the greater the resistance, which means that a larger cable cross-section is required.
The following formula is again applied to calculate the cable cross-section for the respective length of the wires (for 230V alternating current):
A = 2 * L * I * cos φ / y * Ua.
Cable cross-section AWG/inch?
In addition to cables with metric sizes, cables are often also specified according to AWG - the American measure for wire sizes. The following applies to the cable cross-section according to AWG: The wire diameter decreases depending on how long a wire is drawn. The smaller the resulting cable cross-section, the larger the AWG value.
The respective cable cross-sections of an AWG cable can be found in the following table:
| AWG no. | AWG Designation | ∅ in inches |
|
∅ in mm | Area in mm² |
Resistance in Ω/km |
Metric in mm²/km | |
|---|---|---|---|---|---|---|---|---|
| -6 | 0000000 (7/0) | 0,6513 | 0,3332 | 16,54 | 215,0 | - | ||
| -5 | 000000 (6/0) | 0,5801 | 0,2644 | 14,74 | 170,6 | 0,10 | 185 | |
| -4 | 00000 (5/0) | 0,5166 | 0,2096 | 13,12 | 135,3 | 0,13 | 150 | |
| -3 | 0000 (4/0) | 0,4600 | 0,1662 | 11,68 | 107,2 | 0,17 | 120 | |
| -2 | 000 (3/0) | 0,4096 | 0,1318 | 10,40 | 85,01 | 0,21 | 95 | |
| -1 | 00 (2/0) | 0,3648 | 0,1045 | 9,266 | 67,43 | 0,26 | 70 | |
| 0 | (1/0) | 0,3249 | 0,08291 | 8,252 | 53,49 | 0,33 | ||
| 1 | - | 0,2893 | 0,06573 | 7,348 | 42,41 | 0,42 | 50 | |
| 2 | - | 0,2576 | 0,05212 | 6,543 | 33,62 | 0,53 | 35 | |
| 3 | - | 0,2294 | 0,04133 | 5,827 | 26,67 | 0,67 | ||
| 4 | - | 0,2043 | 0,03278 | 5,189 | 21,15 | 0,84 | 25 | |
| 5 | - | 0,1819 | 0,02599 | 4,620 | 16,77 | 1,06 | ||
| 6 | - | 0,1620 | 0,02061 | 4,115 | 13,30 | 1,34 | 16 | |
| 7 | - | 0,1443 | 0,01636 | 3,665 | 10,55 | 1,69 | ||
| 8 | - | 0,1285 | 0,01297 | 3,264 | 8,367 | 2,13 | 10 | |
| 9 | - | 0,1144 | 0,01028 | 2,906 | 6,632 | 2,68 | ||
| 10 | - | 0,1019 | 0,008155 | 2,588 | 5,261 | 3,38 | ||
| 11 | - | 0,09074 | 0,006467 | 2,305 | 4,172 | 4,27 | ||
| 12 | - | 0,08081 | 0,005129 | 2,052 | 3,309 | 5,38 | 4 | |
| 13 | - | 0,07196 | 0,004067 | 1,828 | 2,624 | 6,78 | ||
| 14 | - | 0,06408 | 0,003225 | 1,628 | 2,081 | 8,55 | 2,5 | |
| 15 | - | 0,05707 | 0,002558 | 1,45 | 1,65 | 10,79 | ||
| 16 | - | 0,05082 | 0,002028 | 1,291 | 1,309 | 13,6 | 1,5 | |
| 17 | - | 0,04526 | 0,001609 | 1,15 | 1,038 | 17,15 | ||
| 18 | - | 0,0403 | 0,001276 | 1,024 | 0,8229 | 21,63 | 1 | |
| 19 | - | 0,03589 | 0,01012 | 0,9116 | 0,6527 | 27,27 | 0,75 | |
| 20 | - | 0,03196 | 0,0008022 | 0,8118 | 0,5176 | 34,39 | 0,75 | |
| 21 | - | 0,02846 | 0,0006362 | 0,7229 | 0,4104 | 43,37 | 0,5 | |
| 22 | - | 0,02535 | 0,0005047 | 0,6439 | 0,3256 | 54,66 | 0,34 | |
| 23 | - | 0,02257 | 0,0004001 | 0,5733 | 0,2581 | 68,96 | ||
| 24 | - | 0,0201 | 0,0003173 | 0,5105 | 0,2047 | 86,95 | 0,25 | |
| 25 | - | 0,0179 | 0,0002517 | 0,4547 | 0,1624 | 109,6 | ||
| 26 | - | 0,01594 | 0,0001996 | 0,4049 | 0,1288 | 138,3 | 0,14 | |
| 27 | - | 0,0142 | 0,0001584 | 0,3607 | 0,1022 | 174,2 | ||
| 28 | - | 0,01264 | 0,0001255 | 0,3211 | 0,08096 | 219,9 | 0,09 | |
| 29 | - | 0,01126 | 0,00009958 | 0,286 | 0,06425 | 277,1 | ||
| 30 | - | 0,01003 | 0,00007901 | 0,2548 | 0,05098 | 349,2 | ||
| 31 | - | 0,008928 | 0,0000626 | 0,2268 | 0,04039 | 440,7 | ||
| 32 | - | 0,00795 | 0,00004964 | 0,2019 | 0,03203 | 555,8 | ||
| 33 | - | 0,00708 | 0,00003937 | 0,1798 | 0,0254 | 700,8 | ||
| 34 | - | 0,006305 | 0,00003122 | 0,1601 | 0,02014 | 883,7 | ||
| 35 | - | 0,005615 | 0,00002476 | 0,1426 | 0,01598 | 1114 | ||
| 36 | - | 0,005 | 0,00001964 | 0,127 | 0,01267 | 1405 | ||
| 37 | - | 0,004453 | 0,00001557 | 0,1131 | 0,01005 | 1771 | ||
| 38 | - | 0,003965 | 0,00001235 | 0,1007 | 0,007966 | 2234 | ||
| 39 | - | 0,003531 | 9,792E-06 | 0,089697 | 0,006318 | 2817 | ||
| 40 | - | 0,003145 | 7,768E-06 | 0,07988 | 0,005012 | 3551 | ||
| 41 | - | 0,0028 | 6,158E-06 | 0,07112 | 0,003973 | 4480 | ||
| 42 | - | 0,00249 | 0,00000487 | 0,06325 | 0,003142 | 5665 | ||
| 43 | - | 0,00222 | 3,871E-06 | 0,05639 | 0,002497 | 7127 | ||
| 44 | - | 0,00197 | 3,048E-06 | 0,05004 | 0,001967 | 9051 | ||
| 45 | - | 0,00176 | 2,433E-06 | 0,0447 | 0,00157 | 11340 | ||
| 46 | - | 0,00157 | 1,936E-06 | 0,03988 | 0,001249 | 14251 | ||
| 47 | - | 0,001396 | 1,531E-06 | 0,03546 | 0,0009877 | 18021 | ||
| 48 | - | 0,001243 | 1,214E-06 | 0,03158 | 0,0007832 | 22725 | ||
| 49 | - | 0,001107 | 9,628E-07 | 0,02812 | 0,0006211 | 28657 | ||
| 50 | - | 0,000986 | 7,635E-07 | 0,02504 | 0,0004926 | 36136 |
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